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He beats all bar Obito and his annoying Kamui.
frog genjutsu > kamui
He beats all bar Obito and his annoying Kamui.
frog genjutsu > kamui
Didn't think of that =D
But how will he pull it off with Obito constantly on his toes? The last (and only) time he managed to pull it off he had the locational advantage and his opponent(s) fell for his trap. Obito would never fall for the same trick for obvious reasons.
frog genjutsu > kamui
Obito's jinchuuriki-kage genjustu one shots him.
Get real kid.
He'll stay intangible
I don't think location necessarily had much to do with it. I think all Jiraiya would need to do for prep time is summon Bunta, then have him hop away whenever Obito gets too near.
Ma or Pa break him out of genjutsu.
Jiraiya has a 50/50 of beating Itachi.
Jiraiya beats Pein with intel, i.e. he beats Nagato.
Jiraiya loses to Obito.
Jiraiya beats everyone else with varying difficulty.
So if a perfect jinchuuriki couldn't break a high level kage out of that genjustu.....
What makes you think Ma and Pa will?
So ma and pa are stronger than a fully controlled bijuu?
Yagura was never stated to be a perfect jinchuuriki, he was just noted to be able to control a tailed beast better than most jinchuuriki. Otherwise it's a plothole, since perfect Jins cannot be put under genjutsu.
Controlling a Bijuu translates to perfect Jinchuuriki. Obito controlled the Bijuu first, then the Jinchuuriki. [You must be registered for see links]
Only wins against Deidara, Konan, Hidan, and Zetsu. Loses against the rest.
Loses to Itachi, Orochimaru, Pain and Obito.
Yagura was never stated to be a perfect jinchuuriki, he was just noted to be able to control a tailed beast better than most jinchuuriki. Otherwise it's a plothole, since perfect Jins cannot be put under genjutsu.
By that theoryOh, makes sense. In the event that Obito puts Ma or Pa under a genjutsu Jiraiya can just break them out.
By that theory
Both ma/pa and Jiraiya will be under a genjustu.
Since he believes that he put both the sanbi and yagura under a genjustu.