Sulong Nekomamushi and Inuarashi vs Jack at full power(hybrid form)
If it is 2v1, they shouldn’t need Sulong since they fought him 1v1 in Zuo right?
Jack while in base was able to stalemate both of them and both Neko and Inu had breaks while Jack didn't. So yeah they're gonna need to go Sulong.
Both of them in 1v1 scenarios, that doesn't mean he could stalemate them both if they fought as a team.
Based on his portrayal there is nothing to suggest that he cant.
Both of them in 1v1 scenarios, that doesn't mean he could stalemate them both if they fought as a team.
OT: Luffy had help with Cracker from Nami, he had help a bit from Kata himself, based on that I'd say it'll be a team up.
Guess some of you didn't take hints from Whole Cake Island. Luffy didn't "wreck" Cracker, Luffy didn't "wreck" Katakuri, so how is it apparent that Luffy will just "wreck" one of Kaido's strongest men?
Luffy would wreck cracker now, and cracker > jack
if he couldnt stop them alone, why would he be able to stop them together?
Jack couldn't beat them is because they kept switching out. They each had rest while Jack didn't.
Youre so fking annoying sometimes. Luffy needs no help at all dealing with jack
If they team up its a roflstomp
Luffy would wreck cracker now, and cracker > jack
I believe a team up of some sorts would be necessary. Jack isn't a some random rookie.
On the other hand, i also believe Zoro should defeat him in order to show his true strength after timeskip to us viewers and to show his danger potential to the world, maybe pushing his bounty to 500 million after Wano if he indeeds ends up defeating Jack + for taking part in whats gonna be a big event in Wano Country.
Good for me. Are you annoyed that the manga had Luffy beat a commander with help each time? Whether he needed the help from Kata or not he got it. Whether Luffy needs Zoro or not he's there and the trend indicates it'll be the two of them fighting Jack.
Cracker>Jack based on.....?
Based on it took g4 luffy to be able to break a cracker. And cracker has how many?