NarutoKage2
Active member
In the 4th shinobi world war shikaku naara suspected that Itachi may have been manipulating their shinobi via genjutsu. It was realized it couldn't have been him due to the sheer quantity of shinobi involved.
While we've seen Itachi place S ranked shinobi such as Deidara and Orochimaru under his illusions, what is his numerical limit for multiple opponents at a time?
To answer that i'll postulate a simple hypothesis and an equation. At the beginning of part 2, Itachi showed us his finger genjutsu which ensnared naruto,and shortly after the latter's escape, he put Kakashi's clone under an illusion as well. He was taken out by naruto's rasengan shortly thereafter.
This was a 30% powered Itachi. 30% power=2 genjutsus. The next 60 % power would enable 4 more usages of a similar level of illusion(2+2) leaving Itachi with 10 percent usable power range. Making an allowance for any chakra drained via ninjutsu used in the example referred to above, its safe to assume that he can use at least one more illusion within the last 10 percent(100-(30+60)) of power remaining.
So we have = 2(first 30 percent)+4(next 60)+1(last 10)= 7
Therefore Itachi can place a maximum of 7 opponents under genjutsu simultaneously*
*note: this example assumes genjutsu that are of a sufficient level to incapacitate as opposed to merely stun the target. Also the power level is distributed so that Itachi doesn't die from chakra exhaustion after performing this feat, i.e it is how many genjutsus he can use w.o collapsing. This also assumes a healthy living Itachi.
Agree or disagree?
Edit: In the title, at the same time means that if itachi fought multiple shinobi, how many could he place under genjutsu , it can be successive, i.e one after the other but its still the same fight(time)
While we've seen Itachi place S ranked shinobi such as Deidara and Orochimaru under his illusions, what is his numerical limit for multiple opponents at a time?
To answer that i'll postulate a simple hypothesis and an equation. At the beginning of part 2, Itachi showed us his finger genjutsu which ensnared naruto,and shortly after the latter's escape, he put Kakashi's clone under an illusion as well. He was taken out by naruto's rasengan shortly thereafter.
This was a 30% powered Itachi. 30% power=2 genjutsus. The next 60 % power would enable 4 more usages of a similar level of illusion(2+2) leaving Itachi with 10 percent usable power range. Making an allowance for any chakra drained via ninjutsu used in the example referred to above, its safe to assume that he can use at least one more illusion within the last 10 percent(100-(30+60)) of power remaining.
So we have = 2(first 30 percent)+4(next 60)+1(last 10)= 7
Therefore Itachi can place a maximum of 7 opponents under genjutsu simultaneously*
*note: this example assumes genjutsu that are of a sufficient level to incapacitate as opposed to merely stun the target. Also the power level is distributed so that Itachi doesn't die from chakra exhaustion after performing this feat, i.e it is how many genjutsus he can use w.o collapsing. This also assumes a healthy living Itachi.
Agree or disagree?
Edit: In the title, at the same time means that if itachi fought multiple shinobi, how many could he place under genjutsu , it can be successive, i.e one after the other but its still the same fight(time)
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Oh and Sasuke when he fought those Sound Ninja.
