BelievesItsNotButter
Member
So there has been a lot of talk lately about bijuu's powers being based on the number of tails they have and debate on which is actual the strongest and or how much stronger they are.
I was thinking about this the other day and technically, shouldn't the nine tails be equally as powerful as the combined 1-8?
I say this because the 10 tails is the combined power of all of the bijuu and requires 1-9 just for thats extra tail. By that logic each additional tail should require double the amount of chakra. Which would not be a stretch when we look at the different levels of power naruto possessed when he was unable to control tails and we saw several different numbers and their power. So if this is true, the combined chakra of 1-8 should be equivalent to the 9 tails and 1-7 equivalent to 8 etc etc. That being said, if we look at the different beasts 1-10, 10 being full power chakra level we see:
10 tails = full power
9 tails = 1/2 (minus half since it was sealed away thanks to minato) = 1/4
8 tails = 1/4
7 tails = 1/8
6 tails = 1/16
5 tails = 1/32
4 tails = 1/64
3 tails = 1/128
2 tails = 1/256
1 tails = 1/612
So if this is the case we see that the 9 and 8 tails are the same power and together are half the chakra of the 10 tailed beast. This also means that 1-7 only have 1/4 of the 10 tails charka combined.
Looking at the current situation in the manga, in charka standpoint anyways, this would mean that naruto and bee still have upper hand. However, I am by no means saying it would be easy for them to win. Despite having less chakra they can all still use the abilities of a tailed beast but they will just run out of chakra sooner. They still stand at a disadvantage, they just have more chakra to hold up against them.
So tell me what you think. Should this be an accurate level of how much chakra each bijuu has or is there a flaw in my logic?
I was thinking about this the other day and technically, shouldn't the nine tails be equally as powerful as the combined 1-8?
I say this because the 10 tails is the combined power of all of the bijuu and requires 1-9 just for thats extra tail. By that logic each additional tail should require double the amount of chakra. Which would not be a stretch when we look at the different levels of power naruto possessed when he was unable to control tails and we saw several different numbers and their power. So if this is true, the combined chakra of 1-8 should be equivalent to the 9 tails and 1-7 equivalent to 8 etc etc. That being said, if we look at the different beasts 1-10, 10 being full power chakra level we see:
10 tails = full power
9 tails = 1/2 (minus half since it was sealed away thanks to minato) = 1/4
8 tails = 1/4
7 tails = 1/8
6 tails = 1/16
5 tails = 1/32
4 tails = 1/64
3 tails = 1/128
2 tails = 1/256
1 tails = 1/612
So if this is the case we see that the 9 and 8 tails are the same power and together are half the chakra of the 10 tailed beast. This also means that 1-7 only have 1/4 of the 10 tails charka combined.
Looking at the current situation in the manga, in charka standpoint anyways, this would mean that naruto and bee still have upper hand. However, I am by no means saying it would be easy for them to win. Despite having less chakra they can all still use the abilities of a tailed beast but they will just run out of chakra sooner. They still stand at a disadvantage, they just have more chakra to hold up against them.
So tell me what you think. Should this be an accurate level of how much chakra each bijuu has or is there a flaw in my logic?
