Division of Power Scale through Same-Genesis Multi-Objects

[Lili-Chwan]

As in, standardized rule on what would happen to the actual rank of each object, when created by the same jutsu.
We have reached a consensus that, when a jutsu allows the creation of more than 1 object, each individual object does not carry the total of the rank/chakra/damage, but merely a fraction. It's the totality of all objects which carry the power scales.

Actual example:

S rank jutsu creates 2 fireballs. If we counter only one fireball with an S rank jutsu of our own, ours will overpower our opponent's and carry on, albeit weakened. Now, how much weak? There's no quantifiable amount, at least not standardized.


First I'd like to point out an initial suggestion, which works fairly well in punctual matters, but fails to work correctly on more specific encounters, especially when dealing with stat boosts.

Basic Value Table of Jutsu Encounters, or, as I'd like to call it, Point System. Consist on the attribution of a single value to each rank, and an additional value for elemental weaknesses, in order to preform simple math when two techniques encounter.

E = 1
D = 2
C = 3
B = 4
A = 5
S = 6

So, if two jutsus of the same element (no weakness involved) encounter, but one is of a weaker value, the resulting effect would be a weakened version of the strongest jutsu, following the table:

A rank vs C rank = 5 - 3 = 2, which means attacking jutsu carries on as a D rank.

If elemental weaknesses apply, then 1 value (or more, in double weaknesses) will be added to the vantage jutsu. As in:

A rank vs C rank (vantage) = 5 - (3+1) = 1, which means attacking jutsu carries on as a E rank.

But of course, there is no palpable quantification when stats changes apply, or when two jutsu combine (we can hardly have 2 S ranks to combine following the Point System)

There is another system in play, let's call it Rank System. Where ranks are divided into objects following the rank. Halves will have 2 previous ranks, thirds will have 1 previous rank and 2 previous previous ranks, and so on. Ex:

S rank / 2 = 2 A ranks
A rank / 3 = 2 C ranks + 1 B rank
C rank / 4 = 4 D ranks

This is good, in theory. But is also limited. While combinations can be sort of calculated, we have jutsus of the same rank, so it increases 1 rank overall. If we have jutsus one rank apart, it will only make a stronger version of the highest rank.

2 B ranks combine = 1 A rank
1 A rank and a B rank combine = Strong A rank (T)
1 A rank and a C rank combine = A rank, slightly stronger? (Q)

What if T and Q were to collide? Well, T is stronger than Q, but would come from it?


I figure we could use the actual chakra and damage output, and consider Ranks as being denominations of ranges of chakra/damage points, as such:

Weak E rank/Nothing = 0-4
E = Chakra 5-9, 5 being the standard
D = C 10-14, 10 being the standard
C = 15-19, 15 being the standard
B = 20-29, 20 being the standard
A = 30-39, 30 being the standard
S = 40-Onwards, 40 being the standard

Jutsu would thus be divided evenly, and have the correspondent rank, jutsu that vary less than 5 will be considered almost the same, as such, when a jutsu reaches 0-4 after an encounter, it will be considered as a 0 (with more or less directional splashes)

Now, if a jutsu crates 2 objects, each will have half the power stated in the submission.

S Rank creates 2 objects. 40 / 2 = 20, 2 B Ranks
A rank creates 3 objects = 30 / 3 = 10, 3 D ranks
D rank creates 4 objects = 10 / 4 = 2,5 (Weak E ranks, inefficient standing alone)

If jutsus are combined, the main one (With the elemental advantage) will have it's stats unaltered, while the supporting one will provide half it's stats.

2 B ranks combine, 20 each. 20 + 10 = A rank.
1 C rank (Main)+ 1 A rank = 15 + 15 = 30 A rank.
1 A rank (Main)+ 1 C rank = 30 + 7,5 = 37,5 A rank (Strong A rank)

Stat changes will be carried like so. +5 will add power or even upgrade rank.

B rank + 5 = 20 + 5 = 25 B rank (Strong)
B rank + 10 = 20 + 10 = 30 A rank
B rank + 20 = 20 + 20 = S rank

Now, we would only need to choose a stat change for Elemental weaknesses. I'd say 5 or 10. What do you guys think?

Point System?
Rank System?
Chakra System?

+5, +10?

 

[Drizzy]

I get what you're presenting on the Point System and Chakra System, actually, I use both when I releplay. I'm a bit lost on what you're saying about the Rank Part, I'll read it over a couple more times. It would be great to have an official thread/threads outlining different systems of Battle (like as you said, Point, Chakra, Rank) and how they work.

Below is how I calculate from my knowledge of the RP, it's similar to what you've posted.

Spoiler

• Fire (火, Hi) natured chakra allows for Fire Release (火遁, Katon), which is strong against Wind but weak against Water.
• Wind (風, Kaze) natured chakra allows for Wind Release (風遁, Fūton), which is strong against Lightning but weak against Fire.
• Lightning (雷, Kaminari) natured chakra allows for Lightning Release (雷遁, Raiton), which is strong against Earth but weak against Wind.
• Earth (土, Tsuchi) natured chakra allows for Earth Release (土遁, Doton), which is strong against Water but weak against Lightning.
• Water (水, Mizu) natured chakra allows for Water Release (水遁, Suiton), which is strong against Fire but weak against Earth.

As you can see for Water, it's strong against Fire. However, this doesn't mean it can stop any Fire Jutsu. Here's a little method I use to help when I use techniques, especially to counter an elemental advantage or disadvantage of the element.

Default Power Levels of Jutsu

• D Rank: Power level One
• C Rank: Power level Two
• B Rank: Power level Three
• A Rank: Power level Four
• S Rank: Power level five
• Forbidden Rank: Power level Six

So, each jutsu has it's own power level. Depending on the elemental strength or elemental weakness, I alter the power levels. Fire is weak to water, which means, Water has a higher Element Power than Fire. Here's how I do the math.

1|Step One: Identify the elements

• B Rank Fire Jutsu: Power level Three
• C Rank Water Jutsu : Power Level Two

2|Step Two: Tell if the element has an advantage or disadvantage over the other.

• 
  Depending on the elements, there may not always be an elemental advantage or disadvantage, however, in this case, there is.
• Fire is weak to Wind
• Wind is Strong against Fire

3|Step Three: Calculate the effect of clash
This step is altering Power levels depending on an advantage or disadvantage of the element. If element A is stronger than element B, add +1 power level to element A. Leave element B as it is.

• Water gains +1 to its power level since it is stronger than the Fire element.

4| Step Four: Perform Final Calculations

• Water [C Rank] has power level two (see the default power levels list) +1 power level because the element Water>Fire. Result: Power level Three
• Fire [B Rank] has a power level three (see the default power levels list). No additional power since it's weak to water. Result: Power Level Three

5| Final Results
If the C Rank Water and B rank Fire should clash, they'll cancel each other since after the calculations, they both have a Power Level of Three.
The math is: 3-3=0

Just needs a bit of research and corrections, this may be complicated though since NB has several existing CE's, CJ's etc. that may make alterations to the Systems you posted, it would be great to have something like this worked out though.

Btw, my way of calculating might be wrong in a few parts.

 

[Scorps]

Ok, good idea to make it more official yes.

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The reasoning we currently use to make Cannon techniques and to check customs is the following:

1 S-Rank = 2 A-Ranks = 4 B-Ranks = 8 C-Ranks = 16 D-Ranks

Its used for both multiple projectile techniques, same element combos or multi element combos.

Example:

2 B-Rank fires = A-Rank fire combo

B-Rank fire + B-rank earth = A-Rank Earth/fire combo

B-Rank Fire + A-Rank Water = A-Rank Water/Fire combo

_____________________________

This is all good and what not for the multi projectile issues and the elemental combos but how to figure out the strength left after a clash between 2 techniques?

Example

S-Rank Earth Vs A-Rank Water

First things first, deal with the elemental relations. This would be the same as a S-Rank VS B-Rank of neutral elements.

Now, S-Rank = 4 B-Ranks right? So, take one out and you're left with 3 B-Ranks. 3 B-Ranks creates a strong A-Rank.

Another example:

S-Rank Wind Vs A-Rank Earth

S-rank = 2 A-Ranks right? So, you'd be left with still an A-Rank wind technique.

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This is the reasoning i was taught by the main moderator that, at the time, tried to "guide line" these issues: Izuna Uchiha. And its the reasoning i try to use when judging fights, checking cjs and when fighting. Also, this is all without taking full usage of other concepts like size, concentration, spread, etc. all play a role in this.