Chemistry Homework Help?

[Yusuke Urameshi]

This stuff has to do with thermochemistry. As per usual, any correct answers or legitimate attempts will deserve rep (if I can rep you). Here's the problem:

Suppose that 27g of each of the following substances is initially at 29.0 C. What is the final temperature of each substance upon absorbing 2.30kJ of heat?

- Gold, which has a specific heat capacity of .128 J/g*C.

The formula to use (I think) is:
q (heat) = mass*specific heat capacity*change in temperature (final - initial)


I just need to know how to set it up because there are other, practically identical questions but with different substances. Any help is appreciated!

EDIT: I solved it, but if you still try/put effort into it, I'll give rep because why not?

 

[Cunning Linguist]

I'm getting traumatic flashbacks right now. I assume this is all hypothetical right? Cause gold is not strong at all and very malleable. It would be melted after that heat. But anyway. Just plug the data into the equation. I assume the questions get more difficult from there

 

[Punk Hazard]

You have the formula, just plug the numbers in. I'd help more, but we did this so long ago that I'd have to search for my notes and it's too late for that. If you still need help tomorrow, I'll try to supply more info.

 

[Kai NB]

Took chem last year, completely disregarded, don't care about it anymore

Sorry I can't help. Try Yahoo answers

 

[Uzumaki Macho]

I vaguely remember this. Would it be 2.30kJ = 27g * .128 J/g*C * (X-29) and you are trying to solve for X?

 

[Angelic.]

kamui gg

 

[Arima]

2300 = 27*0.128*(T - 29) ---> solve this and you get T = 694.5 C (final temperature).

Make sure that units on both sides of the equation match. (2300J = 27g*0.128(J/(g*C))*(T - 29)C)

 

[griffnat13]

Took chemistry in Jr year, AP chemistry Sr year (last year), it's in the past for a reason. I hated it... Good luck though champ

 

[Yusuke Urameshi]

I'm getting traumatic flashbacks right now. I assume this is all hypothetical right? Cause gold is not strong at all and very malleable. It would be melted after that heat. But anyway. Just plug the data into the equation. I assume the questions get more difficult from there

You have the formula, just plug the numbers in. I'd help more, but we did this so long ago that I'd have to search for my notes and it's too late for that. If you still need help tomorrow, I'll try to supply more info.

Took chem last year, completely disregarded, don't care about it anymore

Sorry I can't help. Try Yahoo answers

I got it. I'm an idiot and messed up my scientific notation. It wanted the answer (690C) in two sig figs, so 6.9*10^2. Stupid sig figs.

I'll give rep for the help.

 

[Hexuze]

Took chem last year, completely disregarded, don't care about it anymore

Sorry I can't help. Try Yahoo answers

Or join a chemistry forum.

 

[Jiraiyathesannin]

I vaguely remember this. Would it be 2.30kJ = 27g * .128 J/g*C * (X-29) and you are trying to solve for X?

Dude your sig is just mean XD My buddy Derek1st once got something bad a mod said to him in a pm as his sig and they removed it. I wouldn't dare say the mods name though XD

 

[Braveknight]

2300 = 27*0.128*(T - 29) ---> solve this and you get T = 694.5 C (final temperature).

Make sure that units on both sides of the equation match. (2300J = 27g*0.128(J/(g*C))*(T - 29)C)

this, cheers.

 

[The Sach]

2300 = 27*0.128*(T - 29) ---> solve this and you get T = 694.5 C (final temperature).

Make sure that units on both sides of the equation match. (2300J = 27g*0.128(J/(g*C))*(T - 29)C)

there is the solution.

 

[Shuuya]

I absolutely hate chemistry...

 

[DroGGz0r]

I absolutely hate chemistry...

Same, I still struggle with the 7th grade notions, lol
Not really, but you get the point...

 

[Zee Seh]

Dont mek me remember all these >.>

 

[dms_kakashi]

Q=msdt
2300=0.027*128*(t2-29)
T2-29=665.51
T2=694.51

I guess this is required solution.

 

[Conspirator.]

This brings back decent memories from high school.

 

[Yusuke Urameshi]

This brings back decent memories from high school.

It seems you're the only person in this thread in which chemistry bring back good memories. lol

 

[Transcendence]

Convert to proper units so your scientific notation is correct at the end; you're given every number needed for the equation. So just plug them in.