Good . I am not saying you have to be accurate . I know it is impossible to determine it . But I was just asking what do you think of yourself . If you are not sure than just tell me you are not sure . That's all i need .
[Discussion] How intelligent are you?
- Thread starter noor148
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Measure 1: 6 and 6
Measure 2: 3 and 3
Measure 3: 1 and 1 with 1 removed. If both equal, then the outlier's the unique one, but you'll have to extrapolate from the previous two measurements how it is unique.
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In my personal opinion based solely on personal experience, overall, going by popular connotation as opposed to established definition, I would put myself in around 5 or so. Since this is based on my perceived intellectual environment where I received the most stimulation it does not include the lower end so to speak, but I won't use that as an excuse. It is a judgement not so much made based on achievement but on potential, or preliminary ability.
In my personal opinion based solely on personal experience, overall, going by popular connotation as opposed to established definition, I would put myself in around 5 or so. Since this is based on my perceived intellectual environment where I received the most stimulation it does not include the lower end so to speak, but I won't use that as an excuse. It is a judgement not so much made based on achievement but on potential, or preliminary ability.
Measure 2 : which 3 and 3 . lower part of beam balance can be lower because they have the unique one and it is heavier And higher
one could be higher because it could have the unique one and it is less heavy than others .
I mean you don't know if the unique is more or less heavy than usual ones .
(sorry for my english )
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ObitoRolent
Active member
I think you know it was partly a joke. I was just trying to make it funny. For actual intelligence I think i'm a really fast learner and I also have a quite nice bunch of knowledge. I can read a book only once and I get it. I'm sometimes too lazy to actually do stuff that I consider to be too low, but in the end I put in enough effort to make it as quick and efficiently as possible.
If you can't solve it . Then here is a easy one .
Determine the lowest integer ..
If we divide it by 2 remainder is 1 .
If we divide it by 3 remainder is 2 .
If we divide it by 4 remainder is 3 .
If we divide it by 5 remainder is 4 .
If we divide it by 6 remainder is 5 .
If we divide it by 7 remainder is 6 .
If we divide it by 8 remainder is 7 .
If we divide it by 9 remainder is 8 .
If we divide it by 10 remainder is 9 .
Element Master
Active member
Have You Tried Lighting Logs on Fire with a Match it doesn't work you need tinder to start to Fire Dumbass, This Riddle works better if you replace the logs with a Rope ( i have heard it before)
OT: on a scale of 1-10 i am a 7.5-8 i am just really lazy so i don't apply my self
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Hey hey .. Don't get mad about irrelevant topic .If you have heard that one solve this...
There are 20 box of match . Each contains 20 sticks . Each of the sticks weights 10 gram . Now there is one box in which each of the stick weights 9 gram . By measuring weight once figure out which box .
The Sach
Active member
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Answer is 2519.
It can be obtained by simple application of factorials, consider the smallest number divisible by all 10,9,8,7,6,5,4,3,2,1 and calculate it, which can be given by, 2x2x2x3x3x5x7=2520=M+1(because we must get remainder of 1, when it is divided by 2).
Hence, M=2519, which is the solution.
Now to crosscheck it, 2519-1=2518->divisible by 2.
2519-2=2517->divisible by 3.
2519-3=2516->divisible by 4
2519-4=2515, divisible by 5
2519-5=2514, divisible by 6
2519-6=2513, divisible by 7
2519-7=2512, divisible by 8,
2519-8=2511, divisible by 9,
2519-9=2510, divisible by 10.
Correct . But 2520=M+1 is not because it has to be an odd number (not divisible by 2). But because if N is divisible by M then remainder of (N-1)/M is M-1. That's why it works for 1-10 every number .
Now here is another one ...
There is a 10 by 10 box.
Starting from top left and only going right or down how many way you can reach right bottom .
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