*.* Random Trig Question *.* (math)

[DOD_bld]

So I've been in advanced math for a long time now, but randomly my prof threw a trig identity at us, I have been able to get through all of them except one, for some reason, I got hung up on this one.

1+tanX = tan2X+sec2X
1-tanX

I have all of the proofs and laws, but I just can't seem to figure this one out. I am probably just overlooking a tiny nuance, but it really bothers me.

Can anyone help? -- Solved it a few hours ago, thought I'd entertain anyone actually interested in this, with the answer. But prepare yourself, it's a long one. ()

Spoiler

1+tanX = tan2X+sec2X --> working with left side only
1-tanX

Spoiler

the . . periods are solely for placement

1 + sinX/cosX
1 - sinX/cosX

Spoiler

cosX+sinX
. .cosX . .
cosX-sinX
. .cosX . .

Spoiler

cosX+sinX (cosX+sinX)
cosX-sinX (cosX+sinX)

Spoiler

. . .(cosX+sinX)^2 . .
(cosX-sinX)(cosX+sinX)

Spoiler

cos^2X+sin^2X+2sinXcosX
. . .cos^2X-sin^2X

Spoiler

1 + 2sinXcosX
. .cos2X

Spoiler

. 1 . . + 2sinXcosX
cos2X . . cos2X

Spoiler

sec2X + sin2X/cos2X = sec2X+tan2X=tan2X+sec2X

 

[Flaw]

You must be registered for see links

Here you go, my mighty entrepreneur.
It sort of confuses me how a business man such as yourself cannot help himself by making a couple of phone calls or trying the basic search methods, thus resorting to a mere unpopulated board.

 

[Flaw]

lol thanks Flaw! you are correct, the small nuance that I was missing was the google identity proof. It did help!

I didn't see that satire coming. My humblest apologies. Therefore, in order for me to make up for my mistake I offer thee this :

You must be registered for see links

That also comes along with an elderish advice I just made up. You don't walk into a bar of drunks and ask them what's the height of the Eiffel Tower, because there's a slight chance any of them will know the answer, you ****ing cretin.

 

[Flaw]

lol I was serious ... I'm sorry if it came off that way. I am the one who owes the apology.

You have my forgiveness.