NB know Math?(Help with question)

Commander Axe

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Need help with a question. Let's see how much math NB know :p.

Explain why a calculator displays the same value for sin 400 degrees as for sin 40 degrees.
 

gameove

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raph each angle and identify its reference angle.

a. 140°

b. 240°

c. 380°

Solution:

Trigonometric Functions of Any Angle Example 1.svg

a. 140° makes a 40° angle with the x-axis. Therefore the reference angle is 40°.

b. 240° makes a 60° with the x-axis. Therefore the reference angle is 60°.

c. 380° is a full rotation of 360°, plus an additional 20°. So this angle is co-terminal with 20°, and 20° is its reference angle.

If an angle has a reference angle of 30°, 45°, or 60°, we can identify its ordered pair on the unit circle, and so we can find the values of the six trig functions of that angle. For example, above we stated that 150° has a reference angle of 30°. Because of its relationship to 30°, the ordered pair for is 150° is \left ( -\tfrac{\sqrt{3}}{2},\tfrac{1}{2} \right ). Now we can find the values of the six trig functions of 150°:

\cos (150^\circ) = x = \frac{-\sqrt{3}}{2} \sec (150^\circ) = \frac{1}{x} = \frac{1}{\frac{-\sqrt{3}}{2}} = \frac{-2}{\sqrt{3}}
\sin (150^\circ) = y = \frac{1}{2} \csc (150^\circ) = \frac{1}{y} = \frac{1}{\frac{1}{2}} = 2
\tan (150^\circ) = \frac{y}{x} = \frac{\frac{1}{2}}{\frac{-\sqrt{3}}{2}} = \frac{1}{-\sqrt{3}}
 

Commander Axe

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400-360=40
sin(2pi+40)=sin40

Hmm, But wouldn't the top be in the equation if we're talking about Coterminal angles. Dunno this just seems kinda off track, give me a little more explanation to back that up plz.


:ghehe:

Ummmm, I'm of no use. :T_T:

Lol no problem xd, i'm useless to my own assignment as well.
 

Yatori

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Why use calculator when u can copy ur friend answer? :scorps:
 

Mypower

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raph each angle and identify its reference angle.

a. 140°

b. 240°

c. 380°

Solution:

Trigonometric Functions of Any Angle Example 1.svg

a. 140° makes a 40° angle with the x-axis. Therefore the reference angle is 40°.

b. 240° makes a 60° with the x-axis. Therefore the reference angle is 60°.

c. 380° is a full rotation of 360°, plus an additional 20°. So this angle is co-terminal with 20°, and 20° is its reference angle.

If an angle has a reference angle of 30°, 45°, or 60°, we can identify its ordered pair on the unit circle, and so we can find the values of the six trig functions of that angle. For example, above we stated that 150° has a reference angle of 30°. Because of its relationship to 30°, the ordered pair for is 150° is \left ( -\tfrac{\sqrt{3}}{2},\tfrac{1}{2} \right ). Now we can find the values of the six trig functions of 150°:

\cos (150^\circ) = x = \frac{-\sqrt{3}}{2} \sec (150^\circ) = \frac{1}{x} = \frac{1}{\frac{-\sqrt{3}}{2}} = \frac{-2}{\sqrt{3}}
\sin (150^\circ) = y = \frac{1}{2} \csc (150^\circ) = \frac{1}{y} = \frac{1}{\frac{1}{2}} = 2
\tan (150^\circ) = \frac{y}{x} = \frac{\frac{1}{2}}{\frac{-\sqrt{3}}{2}} = \frac{1}{-\sqrt{3}}

I bet you that you got this off the internet. LOL
 

Sir Blades

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you can change the calculator settings for that if possible, and what other people said.
 

Souji

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I miss trig... back when math was easy xd
 

Commander Axe

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It's because every increase in 360 will provide a sin with the same answer.

Oh snap your right! I just confirmed that with Sin20 and Sin 380. Thnx!
raph each angle and identify its reference angle.

a. 140°

b. 240°

c. 380°

Solution:

Trigonometric Functions of Any Angle Example 1.svg

a. 140° makes a 40° angle with the x-axis. Therefore the reference angle is 40°.

b. 240° makes a 60° with the x-axis. Therefore the reference angle is 60°.

c. 380° is a full rotation of 360°, plus an additional 20°. So this angle is co-terminal with 20°, and 20° is its reference angle.

If an angle has a reference angle of 30°, 45°, or 60°, we can identify its ordered pair on the unit circle, and so we can find the values of the six trig functions of that angle. For example, above we stated that 150° has a reference angle of 30°. Because of its relationship to 30°, the ordered pair for is 150° is \left ( -\tfrac{\sqrt{3}}{2},\tfrac{1}{2} \right ). Now we can find the values of the six trig functions of 150°:

\cos (150^\circ) = x = \frac{-\sqrt{3}}{2} \sec (150^\circ) = \frac{1}{x} = \frac{1}{\frac{-\sqrt{3}}{2}} = \frac{-2}{\sqrt{3}}
\sin (150^\circ) = y = \frac{1}{2} \csc (150^\circ) = \frac{1}{y} = \frac{1}{\frac{1}{2}} = 2
\tan (150^\circ) = \frac{y}{x} = \frac{\frac{1}{2}}{\frac{-\sqrt{3}}{2}} = \frac{1}{-\sqrt{3}}

o_0.... WOW xd, thnx for the help though

What does sin mean :confused:

Sin is one of the 3 Trigonometric functions along with Sin, Cos, and Tan.
 

Hypemaster

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yeah its coterminal so it would give the same answer. F*&$ math
 

EgsA

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Hmm, But wouldn't the top be in the equation if we're talking about Coterminal angles. Dunno this just seems kinda off track, give me a little more explanation to back that up plz.

it goes like this


sin(nπ +x) =

1) if n is an odd number, n=2k+1 [k∈Z] than your result will be -sinx

2) if n is an even number, n=2k [k∈Z] than your result will be sinx
 

Commander Axe

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it goes like this


sin(nπ +x) =

1) if n is an odd number, n=2k+1 [k∈Z] than your result will be -sinx

2) if n is an even number, n=2k [k∈Z] than your result will be sinx

Oh i see where your getting at, But temporary Account has already confirmed the Answer, but thnx anyway.
 

EgsA

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Oh i see where your getting at, But temporary Account has already confirmed the Answer, but thnx anyway.

no problem :D

didn't notice, i was to busy searching those stupid symbols xd
 
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