Maths problem - Pythagoras Theorem

[Zenic]

I'm stumped on a simple question, I know the method but this certain method won't work for this question. Here it is:

You must be registered for see images

I know to find the shorter side you have to do: 17 squared - 17 squared but that gives you zero so I tried this other way I used to do:

17 squared + 17 squared = 578

square root of 578 = 24

24 divided by 2 = 12 but the answer is 13

Help please

 

[Jellal Fernandes]

That image isn't working bud.

 

[Keyblade Master Roxas]

Fix the image and I'll help you.

-Key.

 

[Zenic]

That image isn't working bud.

Yeah, sorry

Fix the image and I'll help you.

-Key.

Don't worry 'bout it, figured it out

 

[Darthlawsuit]

I'm stumped on a simple question, I know the method but this certain method won't work for this question. Here it is:

You must be registered for see images

I know to find the shorter side you have to do: 17 squared - 17 squared but that gives you zero so I tried this other way I used to do:

17 squared + 17 squared = 578

square root of 578 = 24

24 divided by 2 = 12 but the answer is 13

Help please

A^2 + B^2 = C^2

The sides along the right angle are a & b. Just square those two, add them, then take sq root to get c.

To get one of the right angle sides just move the equation around. B^2 = C^2 - A^2


The image you posted is not a triangle but a line according to the numbers.