Madara's Chibaku Tensei Calc

[Aikor]

Where did I one CT is the size of the moon?



Velocity isn't speed. And the gravity in NV is same thing as our world, I assume.

But they both share the same law except in velocity u include a direction since its a vector

 

[Wolfus]

But they both share the same law except in velocity u include a direction since its a vector

Thank you. You see, in my country there's no "velocity" and "speed". It's just one word. And it's always a vector in physics. if you want it's module(absolute value), well, then you ask for the module. Of course, in regular conversations, we just say the module. Anyway, in here, the word is "velocidade", which is the displacement(Final position - initial position) divided by the time the displacement took. Better yet, "velocidade" is the derivative of position with respect to time.

 

[Wolfus]

Where did I one CT is the size of the moon?



Velocity isn't speed. And the gravity in NV is same thing as our world, I assume.

Yeah, I suppose. But still, I don't think that's how you calculate the work of madara's force. What I would do is use the gravitational force of each core, then calculate the work made by that force to lift one of those giant rocks(W= F.d)Or we consider the variation of velocity and the variation of height as well, as work would the variation of mecanical energy. And that is disconsidering all the friction(with air)). in both case, we then multiply it by the number of cores. But would be a huge assumption. There's no way to say that there was variation of velocity or that there wasn't.

And what would be the point? To prove that madara can pull out an incredible amount of energy? What's the surprise?

 

[XxLapizxLazulixX]

Madara is country buster

 

[Apêx1]

Yeah, I suppose. But still, I don't think that's how you calculate the work of madara's force. What I would do is use the gravitational force of each core, then calculate the work made by that force to lift one of those giant rocks(W= F.d)Or we consider the variation of velocity and the variation of height as well, as work would the variation of mecanical energy. And that is disconsidering all the friction(with air)). in both case, we then multiply it by the number of cores. But would be a huge assumption. There's no way to say that there was variation of velocity or that there wasn't.

And what would be the point? To prove that madara can pull out an incredible amount of energy? What's the surprise?

As long as you can't calculate the time-frame then there's 0 ways to calculate the Kinetic Energy accurately, you can only calculate potential energy, to an extent.

 

[Benjamin King]

Can you explain how you reached 110 km? I'm confused..

Scaling the width and height of the CT, and divide them to get the overall size of it.

And how did you achieve that velocity, what time-frame did you assume?
KE is most likely single-low double digit Exaton, PE is single digit Exaton which is the safest imo.

The velocity was a tricky part. I did try to apply the velocity of a real world meteor when it enters the atomsphere to NV, except I calculated the distance between the CT and the ground, then divided by seconds.

It only takes about 29.6 Exatons to destroy the moon.

But they both share the same law except in velocity u include a direction since its a vector

Velocity is consistent directed speed, while speed isn't.

Yeah, I suppose. But still, I don't think that's how you calculate the work of madara's force. What I would do is use the gravitational force of each core, then calculate the work made by that force to lift one of those giant rocks(W= F.d)Or we consider the variation of velocity and the variation of height as well, as work would the variation of mecanical energy. And that is disconsidering all the friction(with air)). in both case, we then multiply it by the number of cores. But would be a huge assumption. There's no way to say that there was variation of velocity or that there wasn't.

And what would be the point? To prove that madara can pull out an incredible amount of energy? What's the surprise?

There was no need to calculate each and every one of them. By calculating just one, you can assume the others are the same, since they're roughly same size. Also, read what I said to Apex.

Madara is underrated. Just wanted to spread the message.

 

[Apêx1]

Scaling the width and height of the CT, and divide them to get the overall size of it.



The velocity was a tricky part. I did try to apply the velocity of a real world meteor when it enters the atomsphere to NV, except I calculated the distance between the CT and the ground, then divided by seconds.

It only takes about 29.6 Exatons to destroy the moon.



Velocity is consistent directed speed, while speed isn't.



There was no need to calculate each and every one of them. By calculating just one, you can assume the others are the same, since they're roughly same size. Also, read what I said to Apex.

Madara is underrated. Just wanted to spread the message.

But that still means it takes well over 20 minutes to reach the earth if you estimate it to be at 4.5km above ground and travelling at an average speed of 42 km/s. This isn't even taking into account the fact that they decelerate to a few hundred kilometres an hour once they enter the atmosphere due to atmospheric friction. Narutoforums accurate height calc;

18/3*63 = 378 km tree stump

2*atan(18/(597/tan(70/2))) = 2.418873037964 degrees

Distance from view to stump = 8952.3 km

Stump Ratio = 8/18 = 0.4444444444444444

sin a = 0.4444444444444444

a = arcsin(0.4444444444444444)

sin(arcsin(0.4444444444444444)) = A/8952.3

A = sin(arcsin(0.4444444444444444))*8952.3 = 3978.7 km

That would be the height perpendicular to the stump. Thus, the total height above the ground would be that number + the green line (18 pixels).

Total Height above the ground = 3978.7 + 378 = 4356.7 km

Any top tiers can destroy this in time, not to mention this puts him at continental buster with about 40 exatons.

 

[Eternal Sage]

Can't argue with that.

Smaller meteors can wipe out the dinosaurs. These would knock the planet out of orbit

Smaller meteors come from space, giving them an extremely large amount of momentum

Large chunks still hit the ground, but no noticeable effects

 

[Benjamin King]

But that still means it takes well over 20 minutes to reach the earth if you estimate it to be at 4.5km above ground and travelling at an average speed of 42 km/s. This isn't even taking into account the fact that they decelerate to a few hundred kilometres an hour once they enter the atmosphere due to atmospheric friction. Narutoforums accurate height calc;

Regarding the NF, few members had different results. That member you quoted only scaled the Shinju and ground distance from CT, whereas the thread maker scaled all of them. I'll rethink back to the velocity later after I finish my homework.

 

[Rιver]

This is gold.

 

[Aikor]

Lol reviving old threads?

 

[Holy God]

Together they probably only make up about a tenth of the moon in density. He could easily create more though.