[Discussion] hey is anyone good with math?

[Einstein Mafia]

i have a math final and fourier series is tough can anyone solve the heat equation?

 

[Lokiboriz]

It depends what kind of math

 

[Fair Warning]

lets get at it bitch

 

[Fountain]

i have a math final and fourier series is tough can anyone solve the heat equation?

The heat equation is the opposite to cold.

 

[Solo]

Depends. What's the problem?

 

[SBL7]

Bring it on!!!!!!!!

 

[Zatack]

Q = mcΔT or Q=cpmΔT

Q is the amount of heat needed to change the temperature of a substance

m is the mass of the heated substance
cp is the specific heat capacity (if this is what you're looking for, then the equation should be Q / mΔT = cp )
ΔT (delta T) is the temperature difference; the difference in temperature before and after you applied the heat

These two equations should get you through it np

 

[Einstein Mafia]

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this it

 

[Zatack]

You are aware that, that link is an empty function not a real question right????

 

[Aim64C]

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this it

As Zatack stated.... that's an empty function.

The "answer" you get is going to depend upon the values to populate it.

I'm very rusty on algebra of that nature, but you're going to have to go through a page worth of reductions to the equation to finally isolate the variable(s) and determine their values. Depending upon how much information you have, some of those variables are going to remain a function of an unknown variable or combination of variables.

You must be registered for see links

Honestly, though, the nature of this problem is advanced enough that it's relatively difficult to extrapolate any meaning doing it with pen and paper. Unless you are tasked with solving for a specific point at a specific time given certain starting conditions... the formula is horribly clunky to use outside of computer modeling (where you can simulate the entire heating and dissipation process in three dimensions).

 

[Einstein Mafia]

sorry for that but our lecturer is a madman because he said you have to solve it as x=0,x=-a,x=+a wat does dat mean and he never gave no hints

 

[Aim64C]

sorry for that but our lecturer is a madman because he said you have to solve it as x=0,x=-a,x=+a wat does dat mean and he never gave no hints

x, in this equation, is in regards to the x coordinate. I'm going to operate (perhaps erroneously) on the assumption that you are simply talking about a one-dimensional setup (such as a rod, wire, etc).

I have no idea what the heck "a" is. It might be a variable specifically used by your course... But in order to graph your function (again, assuming a single dimension), you're going to have to plot a few points by resolving a few values for x and connecting them with the appropriate function (in this case, a parabolic function).

Unless your challenge is to graph the temperature of a given point (or points) over a period of time - in which case x is defined and you are graphing the temperature over time (so your variable is time).

You do understand how to isolate and solve for variables in these equations, don't you? ... Because explaining how to do that over internet forums is a pain in the ass... and, as I said, I'm a bit rusty on it.

 

[Einstein Mafia]

i real good in math but learning to derive equationa that mean

 

[shonu]

sorry for that but our lecturer is a madman because he said you have to solve it as x=0,x=-a,x=+a wat does dat mean and he never gave no hints

He means to say U should Substitute those Values for x to derive the Answer!!

 

[Aim64C]

i real good in math but learning to derive equationa that mean

I'm ... not entirely sure I'm understanding your sentence, here...

the variable 'a' would be an arbitrarily chosen value for x that falls within the bounds of your setup.

x=0 is (theoretically) the middle-point of your medium with negative values for x representing a heated side with positive values representing an unheated side (or vice-versa).

By plotting a and -a, you get two points of equal distance from your center point (which at t>0 becomes the equilibrium temperature... which is 50% of 'delta t' assuming objects of equal mass, distribution, and composition) - which allows you to graph an appropriate parabola to illustrate the function.

Unless I'm wrong, here. I -think- you can graph that with just three points (though, really, a and -a should be mirrors of each other across both the x and 'y' axis since 'y' in this graph represents the temperature across a single dimension... things get more complicated if we are computing this across two dimensions and the y axis represents a place rather than a solved value).

 

[6ari8]

This is a three-dimensional heat problem. As I can remember, you need to separate the function U(x,y,z,t) into the product of four functions. By assumption U(x,y,z,t)= X(x) Y Z(z) T(t) , substitute this into the main equation, separate the variables, define a constant of separation, in the end you get four ODEs (each for the particular variable) that you need to solve separately using the boundary conditions.

 

[Strawberry]

what is the question