- Joined
- Feb 8, 2011
- Messages
- 32,590
- Reaction score
- 2,096
Hey bae :* why didnt you tell me you liked nardo?
Because cheaters don't usually confess unless caught. <3
Hey bae :* why didnt you tell me you liked nardo?
Nup, haven't.:|
So you want me to say, you are legend? Okay, you are legend.U_U
Nup, haven't.:|
So you want me to say, you are legend? Okay, you are legend.U_U
Why you did that to me bae??? I thought, we were in relationship.:T_T:
Fine I did it, but stay away from Yama.u.uThanks you Sach all i wanted was for you to except me :,)
We are in a relationship.
You must be registered for see images
Maxima and Minima can be local or global, I believe it is local in her case. So you better find local maximas and minimas.
l0l enjoy yourself.
You gonna be tangential to her function? Or are you gonna be orthogonal to her curve? You get me? Your 'm' will be the negative reciprocal of hers, eh?
Don't worry, I'll find her second derivative and determine hence whether or not any of her stationary points are maxima or minima. Or, I could find f'(x + Δx) and f'(x - Δx) and ascertain whether or not the corresponding gradient functions are positive and negative, and hence espy the nature of the stationary point. :--)
l0l u get me, dawg?
l0l enjoy yourself.
You gonna be tangential to her function? Or are you gonna be orthogonal to her curve? You get me? Your 'm' will be the negative reciprocal of hers, eh?
Don't worry, I'll find her second derivative and determine hence whether or not any of her stationary points are maxima or minima. Or, I could find f'(x + Δx) and f'(x - Δx) and ascertain whether or not the corresponding gradient functions are positive and negative, and hence espy the nature of the stationary point. :--)
l0l u get me, dawg?
Fine I did it, but stay away from Yama.u.u
You must be registered for see images
That's why.
l0l enjoy yourself.
You gonna be tangential to her function? Or are you gonna be orthogonal to her curve? You get me? Your 'm' will be the negative reciprocal of hers, eh?
Don't worry, I'll find her second derivative and determine hence whether or not any of her stationary points are maxima or minima. Or, I could find f'(x + Δx) and f'(x - Δx) and ascertain whether or not the corresponding gradient functions are positive and negative, and hence espy the nature of the stationary point. :--)
l0l u get me, dawg?
Then they have to do cross product for better yield, but the result will be a vector with direction and magnitude.u.uHahah nice. But if they are orthogonal, won't their dot products be zero? Not very conductive towards reproduction.
I am ready to do anything for you darling, you know that, don't you?>_OSelfish eh? As long as you admit that you're the one in the wrong.
l0l enjoy yourself.
You gonna be tangential to her function? Or are you gonna be orthogonal to her curve? You get me? Your 'm' will be the negative reciprocal of hers, eh?
Don't worry, I'll find her second derivative and determine hence whether or not any of her stationary points are maxima or minima. Or, I could find f'(x + Δx) and f'(x - Δx) and ascertain whether or not the corresponding gradient functions are positive and negative, and hence espy the nature of the stationary point. :--)
l0l u get me, dawg?
Then they have to do cross product for better yield, but the result will be a vector with direction and magnitude.u.u
I am ready to do anything for you darling, you know that, don't you?>_O
OT-OP this is true love. Learn something.u.u
Fine I did it, but stay away from Yama.u.u
You must be registered for see images
That's why.
Maxima and Minima can be local or global, I believe it is local in her case. So you better find local maximas and minimas.
Also I think he will be tangential considering the fact that he already admitted that getting her is his achievement.
This is my conclusion based upon my observations and my experience in this field, but you can still do paperwork and verify my results.u.u
Hahah nice. But if they are orthogonal, won't their dot products be zero? Not very conductive towards reproduction.
I don't even know how to translate that man
Then they have to do cross product for better yield, but the result will be a vector with direction and magnitude.u.u
I am ready to do anything for you darling, you know that, don't you?>_O
OT-OP this is true love. Learn something.u.u
You are 1 cheeky cyunt m8. xD
By the way guys, I wrote a short PDF on integration from first principles. Want to read? I didn't finish it; the example got boring and I needed to learn a particular case for summation that I wasn't aware of previously, and I ended writing other PDFs. >_>
Just PM me if you want m8s.
OP you are.
You must be registered for see images
^ that's pretty much the point here.