2nd degree equation

[le sarkozy faec]

Assuming that the roots of the following equation are prime numbers, calculate the value of K.

x²-3KX+7=0


i forgot how to maths. halp

 

[Sasori]

I don't that is the right answer to that equation.

 

[Lt Fresh]

Taking a stab here and assuming that I understand what you're saying I believe K= +/- (2sqrt(7))/3
-is x^2 and X the same variable?

 

[Nebula 868]

Assuming that the roots of the following equation are prime numbers, calculate the value of K.

x²-3KX+7=0


i forgot how to maths. halp

Since the roots of the equations are prime numbers that also means they are real so use the equation (b^2 - 4ac ≥ 0) where b=3k, a=1 and c=7.

So from that K= square root (28/9) or ± 1.76

I think this is the answer.

 

[Tsunade123]

Use this

You must be registered for see images

It's not that equation

 

[IcedFox]

42!

I know that it would come in handy one day.

 

[Scooby Doo]

It's not that equation

He can always check from that if b^2 - 4ac is >= 0

 

[Uzumaki Naruta]

Assuming that the roots of the following equation are prime numbers, calculate the value of K.

x²-3KX+7=0


i forgot how to maths. halp

Don´t really think that if the roots are prime numbers this would be possible, since numbers with decimals can´t count as prime. Negative numbers can´t be prime numbers (since they have another factor which is -1 and its number)

I thought of having roots 7 and 1. 7 is a prime number but 1 isn´t.

Now I´m wondering...

X1 . X2 = c/a = 7

Meaning that the two roots when multiplying must be 7, which means 2 prime numbers multiplying must be 7, which in my opinion is not possible.

The only option I have closest to the given conditions are 7 (prime number) and 1 (not a prime number).

In that case:
X1 = 7
x²-3KX+7=0
49 - 21K +7 = 0
21K = 56
K = 56 / 21 = 8 / 3

X2 = 1
x²-3KX+7=0
1 - 3K +7 = 0
3k = 8
K = 8/3

So the value of K is 8/3.
Note that this is the closest answer I can give to your given conditions since 1 is not considered as Prime number.
If both roots were really prime numbers, then I don´t think it´s possible to solve K.

 

[le sarkozy faec]

guise u do not understand i need to know how to solve this crap, i aint needing just the answer

Wow how could you forget how to maths

idk u forgot how to dog

 

[le sarkozy faec]

Don´t really think that if the roots are prime numbers this would be possible, since numbers with decimals can´t count as prime. Negative numbers can´t be prime numbers (since they have another factor which is -1 and its number)

I thought of having roots 7 and 1. 7 is a prime number but 1 isn´t.

Now I´m wondering...

X1 . X2 = c/a = 7

Meaning that the two roots when multiplying must be 7, which means 2 prime numbers multiplying must be 7, which in my opinion is not possible.

The only option I have closest to the given conditions are 7 (prime number) and 1 (not a prime number).

In that case:
X1 = 7
x²-3KX+7=0
49 - 21K +7 = 0
21K = 56
K = 56 / 21 = 8 / 3

X2 = 1
x²-3KX+7=0
1 - 3K +7 = 0
3k = 8
K = 8/3

So the value of K is 8/3.
Note that this is the closest answer I can give to your given conditions since 1 is not considered as Prime number.
If both roots were really prime numbers, then I don´t think it´s possible to solve K.

thanks. pos reply

 

[Retro Chaos]

The answer is Carbon-12.