BSM Naruto's Destructive Power Capacity

What do you think is the level of BSM Naruto's Destructive Power Capacity?

  • City/Mountain Level

    Votes: 9 18.8%
  • Island Level

    Votes: 18 37.5%
  • Country Level

    Votes: 16 33.3%
  • Continental Level

    Votes: 5 10.4%

  • Total voters
    48

Retsu

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Country level? What... Maybe a real small one.. do you realize how big a country can be?

Sasori was said to have defeated a country with his 100 puppets, Naruto easily outclasses him on a destructive scale so he could take out a country pretty easily and leave nothing but scorched earth in his wake.
 

Murasame

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Sasori was said to have defeated a country with his 100 puppets, Naruto easily outclasses him on a destructive scale so he could take out a country pretty easily and leave nothing but scorched earth in his wake.
Well isn't this thread talking about his DC as in how much his attacks can destroy an area?
 

Murasame

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I honestly can't answer that
Well thats what I'm referring to. Lol Well if we were to talk about him going on a rampage I'd maybe agree with you depending on the size of the country.
 

Rainbow Dash

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well, first of all distance from crater to the PoV (panel height = 1300 there)

2*atan(366.55/(1300/tan(70/2))) = 22.33672801645718 degrees

size = 99.68km



distance = 252.44 km .. that is like the hypotenuse of a triangle

You must be registered for see images


we need that angle to get height .. we can get it

we know that the crater is in fact, a circle, yet the blue diameter in pic is much shorter then the red .. perspective ! we have a ratio of how much shorter the distance looks then it really is

crater : 78.02/366.55 = 0.21284954303642

You must be registered for see images


orange line = perceived size

red line = real

we have both .. angle ABC is 90degrees and sinA = BC/AC = half of perceived / half of real .. it's our earlier 0.21284954303642 ratio

so sin A = 0.21284954303642
A = 12.289395228244101160346986154081 degrees

so sin(12.289395228244101160346986154081) = height/252.44

height = 252.44 * sin(12.289395228244101160346986154081) = 53.73 km


now getting mountain size & crater depth :

mountain's further back from the center and red diameter, so angsizing

distance is what we have for crater + crater radius, so 252.44 + (99.68/2) = 302.28 km .. this isn't strictly correct, since the line isn't straight, but rather composed of 2 lines ("hypotenuse" + horizontal radius), but the angle is so narrow that it won't matter much .. just to be sure I'll take it as 290km

2*atan(40/(1300/tan(70/2))) = 2.46847575234475 degrees

distance = 290 km



mountain diameter = 12.496 km

mountain height = 9.75/40*12.496 = 3.0459 km

crater depth = 22.25/40*12.496 = 6.9509 km

Once again:

Mountain in the back of the crater Height = 3.0459 km

Mountain in the back of the crater Diameter = 12.496 km

destroyed half of this mountain at the edge of the crater

destroyed volume = (1/3*pi*r^2*h)/2 = (1/3*pi*(12496/2)^2*3046)/2 = 62260207398.09 m^3

energy = 62260207398.09 * 1000000 * 214.35 = 13345475455780591500 J

cross-section area = 1/2*b*h = 1/2*12496*3046 = 19031408 m^2


J/m^2 = 13345475455780591500/19031408 = 701234267889.2 J/m^2

surface area of dome = 2*pi*r^2 = 2*pi*49840^2 = 15607593152.578 m^2

Total yield = 701234267889.2*15607593152.578 = 10944579157860524821598 J = 2615817 MT = 2.61 Teraton

For his Bijuudama to be considered Country Level, he would need to output over 7 teratons of kinetic energy.
 

XxLotusxX

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He could reduce a country to ashes given some time. Taking into consideration how long he has been fighting in this war, would he have the power and stamina to go against the entire alliance in a hypothetical situation? no kages included.
 

O n y x

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If he going crazy and spamming his moves.. I would say a village, maybe a bit more.
 

Professor Finesser

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well, first of all distance from crater to the PoV (panel height = 1300 there)

2*atan(366.55/(1300/tan(70/2))) = 22.33672801645718 degrees

size = 99.68km



distance = 252.44 km .. that is like the hypotenuse of a triangle

You must be registered for see images


we need that angle to get height .. we can get it

we know that the crater is in fact, a circle, yet the blue diameter in pic is much shorter then the red .. perspective ! we have a ratio of how much shorter the distance looks then it really is

crater : 78.02/366.55 = 0.21284954303642

You must be registered for see images


orange line = perceived size

red line = real

we have both .. angle ABC is 90degrees and sinA = BC/AC = half of perceived / half of real .. it's our earlier 0.21284954303642 ratio

so sin A = 0.21284954303642
A = 12.289395228244101160346986154081 degrees

so sin(12.289395228244101160346986154081) = height/252.44

height = 252.44 * sin(12.289395228244101160346986154081) = 53.73 km


now getting mountain size & crater depth :

mountain's further back from the center and red diameter, so angsizing

distance is what we have for crater + crater radius, so 252.44 + (99.68/2) = 302.28 km .. this isn't strictly correct, since the line isn't straight, but rather composed of 2 lines ("hypotenuse" + horizontal radius), but the angle is so narrow that it won't matter much .. just to be sure I'll take it as 290km

2*atan(40/(1300/tan(70/2))) = 2.46847575234475 degrees

distance = 290 km



mountain diameter = 12.496 km

mountain height = 9.75/40*12.496 = 3.0459 km

crater depth = 22.25/40*12.496 = 6.9509 km

Once again:

Mountain in the back of the crater Height = 3.0459 km

Mountain in the back of the crater Diameter = 12.496 km

destroyed half of this mountain at the edge of the crater

destroyed volume = (1/3*pi*r^2*h)/2 = (1/3*pi*(12496/2)^2*3046)/2 = 62260207398.09 m^3

energy = 62260207398.09 * 1000000 * 214.35 = 13345475455780591500 J

cross-section area = 1/2*b*h = 1/2*12496*3046 = 19031408 m^2


J/m^2 = 13345475455780591500/19031408 = 701234267889.2 J/m^2

surface area of dome = 2*pi*r^2 = 2*pi*49840^2 = 15607593152.578 m^2

Total yield = 701234267889.2*15607593152.578 = 10944579157860524821598 J = 2615817 MT = 2.61 Teraton

For his Bijuudama to be considered Country Level, he would need to output over 7 teratons of kinetic energy.

You soloed the thread
 

D R E X

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well, first of all distance from crater to the PoV (panel height = 1300 there)

2*atan(366.55/(1300/tan(70/2))) = 22.33672801645718 degrees

size = 99.68km



distance = 252.44 km .. that is like the hypotenuse of a triangle

You must be registered for see images


we need that angle to get height .. we can get it

we know that the crater is in fact, a circle, yet the blue diameter in pic is much shorter then the red .. perspective ! we have a ratio of how much shorter the distance looks then it really is

crater : 78.02/366.55 = 0.21284954303642

You must be registered for see images


orange line = perceived size

red line = real

we have both .. angle ABC is 90degrees and sinA = BC/AC = half of perceived / half of real .. it's our earlier 0.21284954303642 ratio

so sin A = 0.21284954303642
A = 12.289395228244101160346986154081 degrees

so sin(12.289395228244101160346986154081) = height/252.44

height = 252.44 * sin(12.289395228244101160346986154081) = 53.73 km


now getting mountain size & crater depth :

mountain's further back from the center and red diameter, so angsizing

distance is what we have for crater + crater radius, so 252.44 + (99.68/2) = 302.28 km .. this isn't strictly correct, since the line isn't straight, but rather composed of 2 lines ("hypotenuse" + horizontal radius), but the angle is so narrow that it won't matter much .. just to be sure I'll take it as 290km

2*atan(40/(1300/tan(70/2))) = 2.46847575234475 degrees

distance = 290 km



mountain diameter = 12.496 km

mountain height = 9.75/40*12.496 = 3.0459 km

crater depth = 22.25/40*12.496 = 6.9509 km

Once again:

Mountain in the back of the crater Height = 3.0459 km

Mountain in the back of the crater Diameter = 12.496 km

destroyed half of this mountain at the edge of the crater

destroyed volume = (1/3*pi*r^2*h)/2 = (1/3*pi*(12496/2)^2*3046)/2 = 62260207398.09 m^3

energy = 62260207398.09 * 1000000 * 214.35 = 13345475455780591500 J

cross-section area = 1/2*b*h = 1/2*12496*3046 = 19031408 m^2


J/m^2 = 13345475455780591500/19031408 = 701234267889.2 J/m^2

surface area of dome = 2*pi*r^2 = 2*pi*49840^2 = 15607593152.578 m^2

Total yield = 701234267889.2*15607593152.578 = 10944579157860524821598 J = 2615817 MT = 2.61 Teraton

For his Bijuudama to be considered Country Level, he would need to output over 7 teratons of kinetic energy.


I see one flaw in your calculation .
 

Danielgf04

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It's either island or country level... Don't think it's continental, that's overhyping BSM. Mountain level... There's no way he's just mountain level...

So yeah, Island level or Country level, though Island level might be more truthful...
 

6ari8

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Each of the 5 Bijuu destroyed a mountin as I remember and Naruto's first BM transformation was easily able to match their combined Bijuudama. I think BSM is closer to country level than anything else.
 

crono0929

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well, first of all distance from crater to the pov (panel height = 1300 there)

2*atan(366.55/(1300/tan(70/2))) = 22.33672801645718 degrees

size = 99.68km



distance = 252.44 km .. That is like the hypotenuse of a triangle

You must be registered for see images


we need that angle to get height .. We can get it

we know that the crater is in fact, a circle, yet the blue diameter in pic is much shorter then the red .. Perspective ! We have a ratio of how much shorter the distance looks then it really is

crater : 78.02/366.55 = 0.21284954303642

You must be registered for see images


orange line = perceived size

red line = real

we have both .. Angle abc is 90degrees and sina = bc/ac = half of perceived / half of real .. It's our earlier 0.21284954303642 ratio

so sin a = 0.21284954303642
a = 12.289395228244101160346986154081 degrees

so sin(12.289395228244101160346986154081) = height/252.44

height = 252.44 * sin(12.289395228244101160346986154081) = 53.73 km


now getting mountain size & crater depth :

Mountain's further back from the center and red diameter, so angsizing

distance is what we have for crater + crater radius, so 252.44 + (99.68/2) = 302.28 km .. This isn't strictly correct, since the line isn't straight, but rather composed of 2 lines ("hypotenuse" + horizontal radius), but the angle is so narrow that it won't matter much .. Just to be sure i'll take it as 290km

2*atan(40/(1300/tan(70/2))) = 2.46847575234475 degrees

distance = 290 km



mountain diameter = 12.496 km

mountain height = 9.75/40*12.496 = 3.0459 km

crater depth = 22.25/40*12.496 = 6.9509 km

once again:

Mountain in the back of the crater height = 3.0459 km

mountain in the back of the crater diameter = 12.496 km

destroyed half of this mountain at the edge of the crater

destroyed volume = (1/3*pi*r^2*h)/2 = (1/3*pi*(12496/2)^2*3046)/2 = 62260207398.09 m^3

energy = 62260207398.09 * 1000000 * 214.35 = 13345475455780591500 j

cross-section area = 1/2*b*h = 1/2*12496*3046 = 19031408 m^2


j/m^2 = 13345475455780591500/19031408 = 701234267889.2 j/m^2

surface area of dome = 2*pi*r^2 = 2*pi*49840^2 = 15607593152.578 m^2

total yield = 701234267889.2*15607593152.578 = 10944579157860524821598 j = 2615817 mt = 2.61 teraton

for his bijuudama to be considered country level, he would need to output over 7 teratons of kinetic energy.


holy mother of god!!!
 

Byron123

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Well to be fair that scan is inaccurate because here wee see distraction produced by the collision of BM Kurama's Yang half along with the TBB of 5 tailed beasts so if you consider that Yang was capable of cancelling a power of equal force then from what it is seen in the panel, Kurama's alone Yang TBB would produce the exact half damage.
 

9tailsJinchuuriki

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Multiple mountain buster without an issue; He could nail an island pretty bad. But he can't annihilate it.

I'm going with this^

You should know that the blast went off in the sky. If it hit the ground, who knows how much damage it would've made. So him being able to annihilate an island is questionable...
 

GodaimeRaikage

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At most a village.The people saying a country of a continent are high off crack/meth/dope.A tail beast bomb from a both ying and Yang Kurama can't get near the destructive force of destructing a country;this was proven back when Minato took on Kurama and warp a tail beast bomb away from the village.Go back to that chapter and look at the destruction that tail beast bomb did.Now you think adding Sage Chakra to a tail beast bomb can destruct a country? I hope these morons making said claim realize that Naruto still can only absorb a set amount of Sage Chakra.
 

AGoodBoy

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Less than the size of the explosion in your scan. That's 7 TBB's Exploding together :|
 

CrimsonReaper

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well, first of all distance from crater to the PoV (panel height = 1300 there)

2*atan(366.55/(1300/tan(70/2))) = 22.33672801645718 degrees

size = 99.68km



distance = 252.44 km .. that is like the hypotenuse of a triangle

You must be registered for see images


we need that angle to get height .. we can get it

we know that the crater is in fact, a circle, yet the blue diameter in pic is much shorter then the red .. perspective ! we have a ratio of how much shorter the distance looks then it really is

crater : 78.02/366.55 = 0.21284954303642

You must be registered for see images


orange line = perceived size

red line = real

we have both .. angle ABC is 90degrees and sinA = BC/AC = half of perceived / half of real .. it's our earlier 0.21284954303642 ratio

so sin A = 0.21284954303642
A = 12.289395228244101160346986154081 degrees

so sin(12.289395228244101160346986154081) = height/252.44

height = 252.44 * sin(12.289395228244101160346986154081) = 53.73 km


now getting mountain size & crater depth :

mountain's further back from the center and red diameter, so angsizing

distance is what we have for crater + crater radius, so 252.44 + (99.68/2) = 302.28 km .. this isn't strictly correct, since the line isn't straight, but rather composed of 2 lines ("hypotenuse" + horizontal radius), but the angle is so narrow that it won't matter much .. just to be sure I'll take it as 290km

2*atan(40/(1300/tan(70/2))) = 2.46847575234475 degrees

distance = 290 km



mountain diameter = 12.496 km

mountain height = 9.75/40*12.496 = 3.0459 km

crater depth = 22.25/40*12.496 = 6.9509 km

Once again:

Mountain in the back of the crater Height = 3.0459 km

Mountain in the back of the crater Diameter = 12.496 km

destroyed half of this mountain at the edge of the crater

destroyed volume = (1/3*pi*r^2*h)/2 = (1/3*pi*(12496/2)^2*3046)/2 = 62260207398.09 m^3

energy = 62260207398.09 * 1000000 * 214.35 = 13345475455780591500 J

cross-section area = 1/2*b*h = 1/2*12496*3046 = 19031408 m^2


J/m^2 = 13345475455780591500/19031408 = 701234267889.2 J/m^2

surface area of dome = 2*pi*r^2 = 2*pi*49840^2 = 15607593152.578 m^2

Total yield = 701234267889.2*15607593152.578 = 10944579157860524821598 J = 2615817 MT = 2.61 Teraton

For his Bijuudama to be considered Country Level, he would need to output over 7 teratons of kinetic energy.[/QUOTE

country level after reading this xd
 
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