Help Pl0x

[Gèckö]

Alright i need assistance with this math problem

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The area of a rectangle is 6x2-5x-4. The width is 2x+1. What is the length?

very simple problem, but i am stuck. Please help!

 

[Perception]

You just need to divide the area by the width to get the length since A = W*L. So,

(6x^2 -5x - 4)/(2x + 1)

First 2x goes into 6x^2 by 3x times. Then you have (6x^2 -5x - 4) - (6x^2 - 3x) = -8x - 4
Finally -4*(2x+1) = -8x - 4
So the answer is 3x - 4.

 

[ShiningStar]

You just need to divide the area by the width to get the length since A = W*L. So,

(6x^2 -5x - 4)/(2x + 1)

First 2x goes into 6x^2 by 3x times. Then you have (6x^2 -5x - 4) - (6x^2 - 3x) = -8x - 4
Finally -4*(2x+1) = -8x - 4
So the answer is 3x - 4.

You just had to steal my thunder, didn't you? XD

 

[Perception]

You just had to steal my thunder, didn't you? XD

I'm sorrrrrrrry =D. Really, I can't resist a math problem, but I'll let you have the next one.

 

[ShiningStar]

I'm sorrrrrrrry =D. Really, I can't resist a math problem, but I'll let you have the next one.

I know how you feel! I am the same way! And you better! I want to solve one so bad! :yayy:

 

[Gèckö]

You just need to divide the area by the width to get the length since A = W*L. So,

(6x^2 -5x - 4)/(2x + 1)

First 2x goes into 6x^2 by 3x times. Then you have (6x^2 -5x - 4) - (6x^2 - 3x) = -8x - 4
Finally -4*(2x+1) = -8x - 4
So the answer is 3x - 4.

thanks mate^^

 

[Kuroh]

Perdon, yo no hablo ingles.