Solve the math problem.

Perception

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Not even close! Here is the first thing you need to do: You need to set both equations equal to each other and solve for x. The numbers you get will be your intervals. You will need them to set up an integral. Do that and then I will show you how to set up your equation. xd

Wow, you guys are smart. I think you might be smarter that some of the engineers in my class. Seriously though, I wonder of some of them are illiterate. Here is another favorite of mine,

Prove that
a · 0 = 0,∀a ∈ R
 

ShiningStar

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Wow, you guys are smart. I think you might be smarter that some of the engineers in my class. Seriously though, I wonder of some of them are illiterate. Here is another favorite of mine,

Prove that
a · 0 = 0,∀a ∈ R
Oh no I'm not that smart, I just really like Mathematics! As for that problem, I don't think I can solve it as I never seen anything like that before. Maybe after I have taken AP Calculus I will! Can you tell me what type of equation that is and how to solve it?
 

Perception

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Oh no I'm not that smart, I just really like Mathematics! As for that problem, I don't think I can solve it as I never seen anything like that before. Maybe after I have taken AP Calculus I will! Can you tell me what type of equation that is and how to solve it?

This is from Real Analysis. Basically its a proofs of calculus course. It's real nasty, I HATED IT!!!! In this course you start off with these rules, (R Means real numbers)

For all a, b,c ∈ R, (a + b) + c = a + (b + c). (+ associative)
For all a, b ∈ R, a + b = b + a. (+ commutative)
There exists 0 ∈ R such that for all a ∈ R, a + 0 = a. (Zero)
For all a ∈ R, there exists (−a) ∈ R such that a + (−a) = 0.
For all a, b,c ∈ R, (a · b) · c = a · (b · c). (· associative)
For all a, b ∈ R, a · b = b · a. (· commutative)
There exists 1 ∈ R, 1 not equal to 0, such that for all a ∈ R, a · 1 = a. (Unit)
For non-zero a in R, there exists (1/a) ∈ R such that a · (1/a) = 1. (Reciprocals)
For all a, b,c ∈ R, a · (b + c) = a · b + a · c. (Distributive)

The course is about proving everything in calculus starting from those rules. To solve the problem I wrote, you have to prove it with the rules above.
 
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SasukeUchiha910

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(8/2) + (16/4) + (12/3) + (20/5) + (60/15) + (100/25) + (1000/250) + (10000/2500) + (50000/12500) + (72300/18075) + (300000/75000) + (9635900/2408975) - 44 = :|

unsolvable
 

ShiningStar

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This is from Real Analysis. Basically its a proofs of calculus course. It's real nasty, I HATED IT!!!! In this course you start off with these rules, (R Means real numbers)

For all a, b,c ∈ R, (a + b) + c = a + (b + c). (+ associative)
For all a, b ∈ R, a + b = b + a. (+ commutative)
There exists 0 ∈ R such that for all a ∈ R, a + 0 = a. (Zero)
For all a ∈ R, there exists (−a) ∈ R such that a + (−a) = 0.
For all a, b,c ∈ R, (a · b) · c = a · (b · c). (· associative)
For all a, b ∈ R, a · b = b · a. (· commutative)
There exists 1 ∈ R, 1 not equal to 0, such that for all a ∈ R, a · 1 = a. (Unit)
For non-zero a in R, there exists (1/a) ∈ R such that a · (1/a) = 1. (Reciprocals)
For all a, b,c ∈ R, a · (b + c) = a · b + a · c. (Distributive)

The course is about proving everything in calculus starting from those rules. To solve the problem I wrote, you have to prove it with the rules above.
Oh my goodness that looks extremely tough! Is it okay if you can solve that problem step-by-step so that when I see problems like those, I know what to do? Also, there was "∀" symbol that confused me. I don't know what it is, or what to do with it. :(
 

Perception

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Oh my goodness that looks extremely tough! Is it okay if you can solve that problem step-by-step so that when I see problems like those, I know what to do? Also, there was "∀" symbol that confused me. I don't know what it is, or what to do with it. :(

∀ means "for all". The solution is,

0 is defined as the zero identity, i.e. a + 0 = a for any number a.

Now using the distributive property,

a*0 + a*0 = a*(0 + 0) = a*0

so

a*0 + a*0 = a*0

and we subtract a*0 from both sides to get

a*0 = 0

Looks simple, but is a pain to come up with on your own.
 
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SasukeUchiha910

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Oh my goodness that looks extremely tough! Is it okay if you can solve that problem step-by-step so that when I see problems like those, I know what to do? Also, there was "∀" symbol that confused me. I don't know what it is, or what to do with it. :(

bro you have nothing to prove to this guys when they cant solve these problems ethierZzz , I love math{in 12th}

im goin to take Calculus this and shi.t on

oh and its the internet man, anyone can get the answers for "them" problems
 

Perception

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bro you have nothing to prove to this guys when they cant solve these problems ethierZzz , I love math{in 12th}

im goin to take Calculus this and shi.t on

oh and its the internet man, anyone can get the answers for "them" problems

I agree with this. I just wanted to show a particular type of math I hate doing. I have taken way more math than I should have. I thought I like math, but after the calculus and differential equations it's all about proofs. Not fun.
 

SasukeUchiha910

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I agree with this. I just wanted to show a particular type of math I hate doing. I have taken way more math than I should have. I thought I like math, but after the calculus and differential equations it's all about proofs. Not fun.

wht do you plan to major in?!
 

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4..............................
 

EnDash

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This is from Real Analysis. Basically its a proofs of calculus course. It's real nasty, I HATED IT!!!! In this course you start off with these rules, (R Means real numbers)

For all a, b,c ∈ R, (a + b) + c = a + (b + c). (+ associative)
For all a, b ∈ R, a + b = b + a. (+ commutative)
There exists 0 ∈ R such that for all a ∈ R, a + 0 = a. (Zero)
For all a ∈ R, there exists (−a) ∈ R such that a + (−a) = 0.
For all a, b,c ∈ R, (a · b) · c = a · (b · c). (· associative)
For all a, b ∈ R, a · b = b · a. (· commutative)
There exists 1 ∈ R, 1 not equal to 0, such that for all a ∈ R, a · 1 = a. (Unit)
For non-zero a in R, there exists (1/a) ∈ R such that a · (1/a) = 1. (Reciprocals)
For all a, b,c ∈ R, a · (b + c) = a · b + a · c. (Distributive)

The course is about proving everything in calculus starting from those rules. To solve the problem I wrote, you have to prove it with the rules above.

i think you are the smartest of us all, i like math and physics as theory, in truth i hate to do it lol
 

ShiningStar

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∀ means "for all". The solution is,

0 is defined as the zero identity, i.e. a + 0 = a for any number a.

Now using the distributive property,

a*0 + a*0 = a*(0 + 0) = a*0

so

a*0 + a*0 = a*0

and we subtract a*0 from both sides to get

a*0 = 0

Looks simple, but is a pain to come up with on your own.

Oh wow. Looks like I need a lot of practice! I'm more of a Calculus fangirl, but I'm not that good at proofs. That was the one area I always tried to avoid. I'm going to have to work hard at that if I ever want to become a skilled Mathematician or a Market Analyst for practical applications of math. :heh:
 

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Oh wow. Looks like I need a lot of practice! I'm more of a Calculus fangirl, but I'm not that good at proofs. That was the one area I always tried to avoid. I'm going to have to work hard at that if I ever want to become a skilled Mathematician or a Market Analyst for practical applications of math. :heh:

I'm a PhD student in Structural Engineering, but I have a minor in math.

well if we are at it, can you answer me why someone would want a job as a mathematican? like i can see if you want to be academic or in research or something. but analysis or statistics just seem, well boring. it can be fun trying to solve a real currently unsovlable equation or find imaginitive ways to solve problems quicker or something. but doign the same stuff over and over again just with diffrent data doesn't seem like something you want to work hard for...
 

Perception

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well if we are at it, can you answer me why someone would want a job as a mathematican? like i can see if you want to be academic or in research or something. but analysis or statistics just seem, well boring. it can be fun trying to solve a real currently unsovlable equation or find imaginitive ways to solve problems quicker or something. but doign the same stuff over and over again just with diffrent data doesn't seem like something you want to work hard for...

I really don't like pure math, which is why I stopped liking math after the practical course i.e. calculus, DiffQ. I coudn't imagine writing proofs all day. I like structural engineering because the math may get repetitive at times, but their is always something new to think about. How much has building design changed over the years, a lot. Their will always be challenges in choosing materials and constructing buildings. That's my two cents.
 

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I really don't like pure math, which is why I stopped liking math after the practical course i.e. calculus, DiffQ. I coudn't imagine writing proofs all day. I like structural engineering because the math may get repetitive at times, but their is always something new to think about. How much has building design changed over the years, a lot. Their will always be challenges in choosing materials and constructing buildings. That's my two cents.

hmm, i guess you are right, even things that seem boring and constant now can and do change all the time. like you said architecture isn't the same today as it used to be a 100 years ago and niether to math.
 

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well if we are at it, can you answer me why someone would want a job as a mathematican? like i can see if you want to be academic or in research or something. but analysis or statistics just seem, well boring. it can be fun trying to solve a real currently unsovlable equation or find imaginitive ways to solve problems quicker or something. but doign the same stuff over and over again just with diffrent data doesn't seem like something you want to work hard for...
I know it seems boring and odd, but ever since I was a little girl, I've always had a fascination in numbers. I love calculating things, solving equations, and coming up with new equations to solve. I even remembered when I was in primary school, I was looking at my oldest sisters Pre-Algebra textbook and trying to solve the problems in there. I used to always take my dad's old Calculus textbook (just looking in it surprises me on how much math has changed over time) and just work for hours on trying to complete every problem.

I never had a reason for why I did it, I just did and I loved every second of it. Eventually I was put in higher level Math classes since then, and it shocks me when I solve a problem I struggled with as a child. I just took solace in numbers. When I'm working on equations, I just feel at peace. I can never imagine a year where I am not in a Math class. I just don't think I could function! It's just something I really love to do. I hope I am making sense. :O

A lot of people thought I was weird for it so I usually just keep my love for math hidden. :(
 

Perception

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I know it seems boring and odd, but ever since I was a little girl, I've always had a fascination in numbers. I love calculating things, solving equations, and coming up with new equations to solve. I even remembered when I was in primary school, I was looking at my oldest sisters Pre-Algebra textbook and trying to solve the problems in there. I used to always take my dad's old Calculus textbook (just looking in it surprises me on how much math has changed over time) and just work for hours on trying to complete every problem.

I never had a reason for why I did it, I just did and I loved every second of it. Eventually I was put in higher level Math classes since then, and it shocks me when I solve a problem I struggled with as a child. I just took solace in numbers. When I'm working on equations, I just feel at peace. I can never imagine a year where I am not in a Math class. I just don't think I could function! It's just something I really love to do. I hope I am making sense. :O

A lot of people thought I was weird for it so I usually just keep my love for math hidden. :(

She's going into honored math mode. UV-Integral Jutsu .
 
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